11313140003021 has 2 divisors, whose sum is σ = 11313140003022. Its totient is φ = 11313140003020.

The previous prime is 11313140002987. The next prime is 11313140003023. The reversal of 11313140003021 is 12030004131311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8232658686121 + 3080481316900 = 2869261^2 + 1755130^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313140003021 - 2²⁶ = 11313072894157 is a prime.

Together with 11313140003023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11313140002984 and 11313140003002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313140003023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656570001510 + 5656570001511.

It is an arithmetic number, because the mean of its divisors is an integer number (5656570001511).

Almost surely, 2^{11313140003021} is an apocalyptic number.

It is an amenable number.

11313140003021 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313140003021 is an equidigital number, since it uses as much as digits as its factorization.

11313140003021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11313140003021 its reverse (12030004131311), we get a palindrome (23343144134332).

The spelling of 11313140003021 in words is "eleven trillion, three hundred thirteen billion, one hundred forty million, three thousand, twenty-one".