Base | Representation |
---|---|
bin | 1010010010100000101111… |
… | …0101100000100101011111 |
3 | 1111001112012100101112102122 |
4 | 2210220023311200211133 |
5 | 2440323303430343033 |
6 | 40021104052413155 |
7 | 2245230134022344 |
oct | 244501365404537 |
9 | 44045170345378 |
10 | 11313142434143 |
11 | 3671970a75530 |
12 | 13286906171bb |
13 | 640a94ca48c4 |
14 | 2b17b7d1c7cb |
15 | 149432a52a98 |
hex | a4a0bd6095f |
11313142434143 has 8 divisors (see below), whose sum is σ = 12342052598736. Its totient is φ = 10284306048000.
The previous prime is 11313142434133. The next prime is 11313142434157. The reversal of 11313142434143 is 34143424131311.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11313142434143 - 24 = 11313142434127 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313142434103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18123746 + ... + 18737567.
It is an arithmetic number, because the mean of its divisors is an integer number (1542756574842).
Almost surely, 211313142434143 is an apocalyptic number.
11313142434143 is a deficient number, since it is larger than the sum of its proper divisors (1028910164593).
11313142434143 is a wasteful number, since it uses less digits than its factorization.
11313142434143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36889225.
The product of its digits is 41472, while the sum is 35.
Adding to 11313142434143 its reverse (34143424131311), we get a palindrome (45456566565454).
The spelling of 11313142434143 in words is "eleven trillion, three hundred thirteen billion, one hundred forty-two million, four hundred thirty-four thousand, one hundred forty-three".
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