11313210233 has 4 divisors (see below), whose sum is σ = 12183457188. Its totient is φ = 10442963280.

The previous prime is 11313210229. The next prime is 11313210343. The reversal of 11313210233 is 33201231311.

11313210233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33201231311 = 4441 ⋅7476071.

It can be written as a sum of positive squares in 2 ways, for example, as 4255866169 + 7057344064 = 65237^2 + 84008^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313210233 - 2² = 11313210229 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11313210203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435123458 + ... + 435123483.

It is an arithmetic number, because the mean of its divisors is an integer number (3045864297).

Almost surely, 2^11313210233 is an apocalyptic number.

11313210233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11313210233 is a deficient number, since it is larger than the sum of its proper divisors (870246955).

11313210233 is an equidigital number, since it uses as much as digits as its factorization.

11313210233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 870246954.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 11313210233 its reverse (33201231311), we get a palindrome (44514441544).

The spelling of 11313210233 in words is "eleven billion, three hundred thirteen million, two hundred ten thousand, two hundred thirty-three".