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113132122103 = 71113113019103
BaseRepresentation
bin110100101011100110…
…0110010111111110111
3101211000101001021011102
41221113030302333313
53323143310401403
6123545554000315
711113343112530
oct1512714627767
9354011037142
10113132122103
1143a85151880
1219b1387609b
13a88c390ab0
14569317d687
152e22088b88
hex1a57332ff7

113132122103 has 16 divisors (see below), whose sum is σ = 151897675776. Its totient is φ = 81373753440.

The previous prime is 113132122099. The next prime is 113132122139. The reversal of 113132122103 is 301221231311.

It is a happy number.

It is not a de Polignac number, because 113132122103 - 22 = 113132122099 is a prime.

It is a super-2 number, since 2×1131321221032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113132122153) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56508551 + ... + 56510552.

It is an arithmetic number, because the mean of its divisors is an integer number (9493604736).

Almost surely, 2113132122103 is an apocalyptic number.

113132122103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

113132122103 is a deficient number, since it is larger than the sum of its proper divisors (38765553673).

113132122103 is a wasteful number, since it uses less digits than its factorization.

113132122103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113019134.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 113132122103 its reverse (301221231311), we get a palindrome (414353353414).

The spelling of 113132122103 in words is "one hundred thirteen billion, one hundred thirty-two million, one hundred twenty-two thousand, one hundred three".

Divisors: 1 7 11 13 77 91 143 1001 113019103 791133721 1243210133 1469248339 8702470931 10284738373 16161731729 113132122103