Base | Representation |
---|---|
bin | 10000011101101000000… |
… | …011000001000010110111 |
3 | 11000011010202222020122102 |
4 | 100131220003001002313 |
5 | 122013421414120043 |
6 | 2223415553052315 |
7 | 144510133335116 |
oct | 20355003010267 |
9 | 4004122866572 |
10 | 1131322020023 |
11 | 3a6877872258 |
12 | 16331155709b |
13 | 828b6018030 |
14 | 3ca83325c7d |
15 | 1e6656b96b8 |
hex | 107680c10b7 |
1131322020023 has 64 divisors (see below), whose sum is σ = 1328223536640. Its totient is φ = 954201710592.
The previous prime is 1131322019981. The next prime is 1131322020029. The reversal of 1131322020023 is 3200202231311.
It is not a de Polignac number, because 1131322020023 - 218 = 1131321757879 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131322019977 and 1131322020004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131322020029) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 494673986 + ... + 494676272.
It is an arithmetic number, because the mean of its divisors is an integer number (20753492760).
Almost surely, 21131322020023 is an apocalyptic number.
1131322020023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1131322020023 is a deficient number, since it is larger than the sum of its proper divisors (196901516617).
1131322020023 is a wasteful number, since it uses less digits than its factorization.
1131322020023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2796.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1131322020023 its reverse (3200202231311), we get a palindrome (4331524251334).
The spelling of 1131322020023 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-two million, twenty thousand, twenty-three".
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