11313233303 has 4 divisors (see below), whose sum is σ = 11504983080. Its totient is φ = 11121483528.

The previous prime is 11313233299. The next prime is 11313233329. The reversal of 11313233303 is 30333231311.

11313233303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11313233303 - 2² = 11313233299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313233363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95874800 + ... + 95874917.

It is an arithmetic number, because the mean of its divisors is an integer number (2876245770).

Almost surely, 2^11313233303 is an apocalyptic number.

11313233303 is a deficient number, since it is larger than the sum of its proper divisors (191749777).

11313233303 is an equidigital number, since it uses as much as digits as its factorization.

11313233303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191749776.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 11313233303 its reverse (30333231311), we get a palindrome (41646464614).

The spelling of 11313233303 in words is "eleven billion, three hundred thirteen million, two hundred thirty-three thousand, three hundred three".