11313244013 has 2 divisors, whose sum is σ = 11313244014. Its totient is φ = 11313244012.

The previous prime is 11313244001. The next prime is 11313244051. The reversal of 11313244013 is 31044231311.

11313244013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10846597609 + 466646404 = 104147^2 + 21602^2 .

It is an emirp because it is prime and its reverse (31044231311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11313244013 - 2²² = 11309049709 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11313244013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313241013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656622006 + 5656622007.

It is an arithmetic number, because the mean of its divisors is an integer number (5656622007).

Almost surely, 2^11313244013 is an apocalyptic number.

It is an amenable number.

11313244013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313244013 is an equidigital number, since it uses as much as digits as its factorization.

11313244013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11313244013 its reverse (31044231311), we get a palindrome (42357475324).

The spelling of 11313244013 in words is "eleven billion, three hundred thirteen million, two hundred forty-four thousand, thirteen".