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11313253500 = 2235317487911
BaseRepresentation
bin10101000100101001…
…01000110001111100
31002012102212211020220
422202110220301330
5141132143103000
65110334141340
7550232032233
oct124224506174
932172784226
1011313253500
11488604488a
122238951850
1310b3ab5b53
14794733b1a
1546331a1a0
hex2a2528c7c

11313253500 has 192 divisors, whose sum is σ = 34992082944. Its totient is φ = 2830464000.

The previous prime is 11313253493. The next prime is 11313253561. The reversal of 11313253500 is 535231311.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12418045 + ... + 12418955.

It is an arithmetic number, because the mean of its divisors is an integer number (182250432).

Almost surely, 211313253500 is an apocalyptic number.

11313253500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313253500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17496041472).

11313253500 is an abundant number, since it is smaller than the sum of its proper divisors (23678829444).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313253500 is a wasteful number, since it uses less digits than its factorization.

11313253500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1437 (or 1425 counting only the distinct ones).

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 11313253500 its reverse (535231311), we get a palindrome (11848484811).

The spelling of 11313253500 in words is "eleven billion, three hundred thirteen million, two hundred fifty-three thousand, five hundred".