Base | Representation |
---|---|
bin | 1010010010100001011100… |
… | …0110100011100011111000 |
3 | 1111001112200112001122101122 |
4 | 2210220113012203203320 |
5 | 2440324200322432102 |
6 | 40021134524004412 |
7 | 2245234620450302 |
oct | 244502706434370 |
9 | 44045615048348 |
10 | 11313331452152 |
11 | 3671a58737564 |
12 | 1328723990708 |
13 | 640ac51b5392 |
14 | 2b17d5082972 |
15 | 14944443d0a2 |
hex | a4a171a38f8 |
11313331452152 has 8 divisors (see below), whose sum is σ = 21212496472800. Its totient is φ = 5656665726072.
The previous prime is 11313331452149. The next prime is 11313331452161. The reversal of 11313331452152 is 25125413331311.
It is a tau number, because it is divible by the number of its divisors (8).
It is a super-3 number, since 3×113133314521523 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707083215752 + ... + 707083215767.
It is an arithmetic number, because the mean of its divisors is an integer number (2651562059100).
Almost surely, 211313331452152 is an apocalyptic number.
It is an amenable number.
11313331452152 is a deficient number, since it is larger than the sum of its proper divisors (9899165020648).
11313331452152 is a wasteful number, since it uses less digits than its factorization.
11313331452152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1414166431525 (or 1414166431521 counting only the distinct ones).
The product of its digits is 32400, while the sum is 35.
Adding to 11313331452152 its reverse (25125413331311), we get a palindrome (36438744783463).
The spelling of 11313331452152 in words is "eleven trillion, three hundred thirteen billion, three hundred thirty-one million, four hundred fifty-two thousand, one hundred fifty-two".
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