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11313331452152 = 231414166431519
BaseRepresentation
bin1010010010100001011100…
…0110100011100011111000
31111001112200112001122101122
42210220113012203203320
52440324200322432102
640021134524004412
72245234620450302
oct244502706434370
944045615048348
1011313331452152
113671a58737564
121328723990708
13640ac51b5392
142b17d5082972
1514944443d0a2
hexa4a171a38f8

11313331452152 has 8 divisors (see below), whose sum is σ = 21212496472800. Its totient is φ = 5656665726072.

The previous prime is 11313331452149. The next prime is 11313331452161. The reversal of 11313331452152 is 25125413331311.

It is a tau number, because it is divible by the number of its divisors (8).

It is a super-3 number, since 3×113133314521523 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707083215752 + ... + 707083215767.

It is an arithmetic number, because the mean of its divisors is an integer number (2651562059100).

Almost surely, 211313331452152 is an apocalyptic number.

It is an amenable number.

11313331452152 is a deficient number, since it is larger than the sum of its proper divisors (9899165020648).

11313331452152 is a wasteful number, since it uses less digits than its factorization.

11313331452152 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1414166431525 (or 1414166431521 counting only the distinct ones).

The product of its digits is 32400, while the sum is 35.

Adding to 11313331452152 its reverse (25125413331311), we get a palindrome (36438744783463).

The spelling of 11313331452152 in words is "eleven trillion, three hundred thirteen billion, three hundred thirty-one million, four hundred fifty-two thousand, one hundred fifty-two".

Divisors: 1 2 4 8 1414166431519 2828332863038 5656665726076 11313331452152