Base | Representation |
---|---|
bin | 10101000100101010… |
… | …01101100011010011 |
3 | 1002012110011110212020 |
4 | 22202111031203103 |
5 | 141132212412430 |
6 | 5110341302523 |
7 | 550233230316 |
oct | 124225154323 |
9 | 32173143766 |
10 | 11313404115 |
11 | 4886137a62 |
12 | 2238a04a43 |
13 | 10b3b39580 |
14 | 79477297d |
15 | 463349b10 |
hex | 2a254d8d3 |
11313404115 has 32 divisors (see below), whose sum is σ = 19861692480. Its totient is φ = 5464582656.
The previous prime is 11313404111. The next prime is 11313404117. The reversal of 11313404115 is 51140431311.
It is not a de Polignac number, because 11313404115 - 22 = 11313404111 is a prime.
It is a super-2 number, since 2×113134041152 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11313404111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 537000 + ... + 557669.
It is an arithmetic number, because the mean of its divisors is an integer number (620677890).
Almost surely, 211313404115 is an apocalyptic number.
11313404115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11313404115 is a deficient number, since it is larger than the sum of its proper divisors (8548288365).
11313404115 is a wasteful number, since it uses less digits than its factorization.
11313404115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1094743.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 11313404115 its reverse (51140431311), we get a palindrome (62453835426).
The spelling of 11313404115 in words is "eleven billion, three hundred thirteen million, four hundred four thousand, one hundred fifteen".
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