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11313404115 = 3513531094669
BaseRepresentation
bin10101000100101010…
…01101100011010011
31002012110011110212020
422202111031203103
5141132212412430
65110341302523
7550233230316
oct124225154323
932173143766
1011313404115
114886137a62
122238a04a43
1310b3b39580
1479477297d
15463349b10
hex2a254d8d3

11313404115 has 32 divisors (see below), whose sum is σ = 19861692480. Its totient is φ = 5464582656.

The previous prime is 11313404111. The next prime is 11313404117. The reversal of 11313404115 is 51140431311.

It is not a de Polignac number, because 11313404115 - 22 = 11313404111 is a prime.

It is a super-2 number, since 2×113134041152 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11313404111) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 537000 + ... + 557669.

It is an arithmetic number, because the mean of its divisors is an integer number (620677890).

Almost surely, 211313404115 is an apocalyptic number.

11313404115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11313404115 is a deficient number, since it is larger than the sum of its proper divisors (8548288365).

11313404115 is a wasteful number, since it uses less digits than its factorization.

11313404115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1094743.

The product of its (nonzero) digits is 720, while the sum is 24.

Adding to 11313404115 its reverse (51140431311), we get a palindrome (62453835426).

The spelling of 11313404115 in words is "eleven billion, three hundred thirteen million, four hundred four thousand, one hundred fifteen".

Divisors: 1 3 5 13 15 39 53 65 159 195 265 689 795 2067 3445 10335 1094669 3284007 5473345 14230697 16420035 42692091 58017457 71153485 174052371 213460455 290087285 754226941 870261855 2262680823 3771134705 11313404115