Base | Representation |
---|---|
bin | 10101000100101010… |
… | …10100001000111111 |
3 | 1002012110012211212210 |
4 | 22202111110020333 |
5 | 141132214243403 |
6 | 5110342031503 |
7 | 550233402102 |
oct | 124225241077 |
9 | 32173184783 |
10 | 11313431103 |
11 | 4886156267 |
12 | 2238a18593 |
13 | 10b3b48940 |
14 | 79477c739 |
15 | 463352b03 |
hex | 2a255423f |
11313431103 has 8 divisors (see below), whose sum is σ = 16244926768. Its totient is φ = 6962111424.
The previous prime is 11313431089. The next prime is 11313431123. The reversal of 11313431103 is 30113431311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11313431103 - 212 = 11313427007 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11313431103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313431123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145043950 + ... + 145044027.
It is an arithmetic number, because the mean of its divisors is an integer number (2030615846).
Almost surely, 211313431103 is an apocalyptic number.
11313431103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11313431103 is a deficient number, since it is larger than the sum of its proper divisors (4931495665).
11313431103 is a wasteful number, since it uses less digits than its factorization.
11313431103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 290087993.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 11313431103 its reverse (30113431311), we get a palindrome (41426862414).
The spelling of 11313431103 in words is "eleven billion, three hundred thirteen million, four hundred thirty-one thousand, one hundred three".
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