Base | Representation |
---|---|
bin | 10101000100101010… |
… | …10100001100110111 |
3 | 1002012110012212012222 |
4 | 22202111110030313 |
5 | 141132214300401 |
6 | 5110342032555 |
7 | 550233402605 |
oct | 124225241467 |
9 | 32173185188 |
10 | 11313431351 |
11 | 4886156472 |
12 | 2238a1875b |
13 | 10b3b48aa1 |
14 | 79477c875 |
15 | 463352c1b |
hex | 2a2554337 |
11313431351 has 2 divisors, whose sum is σ = 11313431352. Its totient is φ = 11313431350.
The previous prime is 11313431299. The next prime is 11313431377. The reversal of 11313431351 is 15313431311.
It is a happy number.
It is an a-pointer prime, because the next prime (11313431377) can be obtained adding 11313431351 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11313431351 - 230 = 10239689527 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11313431351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313491351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656715675 + 5656715676.
It is an arithmetic number, because the mean of its divisors is an integer number (5656715676).
Almost surely, 211313431351 is an apocalyptic number.
11313431351 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313431351 is an equidigital number, since it uses as much as digits as its factorization.
11313431351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1620, while the sum is 26.
Adding to 11313431351 its reverse (15313431311), we get a palindrome (26626862662).
The spelling of 11313431351 in words is "eleven billion, three hundred thirteen million, four hundred thirty-one thousand, three hundred fifty-one".
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