11314013220 has 144 divisors (see below), whose sum is σ = 36204954240. Its totient is φ = 2851987968.

The previous prime is 11314013189. The next prime is 11314013251. The reversal of 11314013220 is 2231041311.

11314013220 is a `hidden beast` number, since 11 + 31 + 401 + 3 + 220 = 666.

It is an interprime number because it is at equal distance from previous prime (11314013189) and next prime (11314013251).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 11314013193 and 11314013202.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1662144 + ... + 1668936.

Almost surely, 2^11314013220 is an apocalyptic number.

11314013220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11314013220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18102477120).

11314013220 is an abundant number, since it is smaller than the sum of its proper divisors (24890941020).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11314013220 is a wasteful number, since it uses less digits than its factorization.

11314013220 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7314 (or 7309 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11314013220 its reverse (2231041311), we get a palindrome (13545054531).

The spelling of 11314013220 in words is "eleven billion, three hundred fourteen million, thirteen thousand, two hundred twenty".