Search a number
-
+
11314014520 = 235282850363
BaseRepresentation
bin10101000100101111…
…00010100100111000
31002012111022111011211
422202113202210320
5141132341431040
65110402332504
7550241352034
oct124227424470
932174274154
1011314014520
114886514626
12223905a134
1310b3cc1363
147948911c4
1546341a8ea
hex2a25e2938

11314014520 has 16 divisors (see below), whose sum is σ = 25456532760. Its totient is φ = 4525605792.

The previous prime is 11314014497. The next prime is 11314014577. The reversal of 11314014520 is 2541041311.

It is a super-3 number, since 3×113140145203 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11314014491 and 11314014500.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141425142 + ... + 141425221.

Almost surely, 211314014520 is an apocalyptic number.

11314014520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11314014520 is an abundant number, since it is smaller than the sum of its proper divisors (14142518240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11314014520 is a wasteful number, since it uses less digits than its factorization.

11314014520 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 282850374 (or 282850370 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 11314014520 its reverse (2541041311), we get a palindrome (13855055831).

The spelling of 11314014520 in words is "eleven billion, three hundred fourteen million, fourteen thousand, five hundred twenty".

Divisors: 1 2 4 5 8 10 20 40 282850363 565700726 1131401452 1414251815 2262802904 2828503630 5657007260 11314014520