Base | Representation |
---|---|
bin | 10101000100101111… |
… | …00110101011010001 |
3 | 1002012111100100012210 |
4 | 22202113212223101 |
5 | 141132343000223 |
6 | 5110402542333 |
7 | 550241452014 |
oct | 124227465321 |
9 | 32174310183 |
10 | 11314031313 |
11 | 4886526202 |
12 | 22390679a9 |
13 | 10b3cc8bb0 |
14 | 79489737b |
15 | 463420893 |
hex | 2a25e6ad1 |
11314031313 has 32 divisors (see below), whose sum is σ = 16504298496. Its totient is φ = 6851896128.
The previous prime is 11314031299. The next prime is 11314031329. The reversal of 11314031313 is 31313041311.
11314031313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11314031313 - 26 = 11314031249 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11314031313.
It is not an unprimeable number, because it can be changed into a prime (11314031383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4668220 + ... + 4670642.
It is an arithmetic number, because the mean of its divisors is an integer number (515759328).
Almost surely, 211314031313 is an apocalyptic number.
11314031313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11314031313 is a deficient number, since it is larger than the sum of its proper divisors (5190267183).
11314031313 is a wasteful number, since it uses less digits than its factorization.
11314031313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4293.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 11314031313 its reverse (31313041311), we get a palindrome (42627072624).
It can be divided in two parts, 113140 and 31313, that added together give a triangular number (144453 = T537).
The spelling of 11314031313 in words is "eleven billion, three hundred fourteen million, thirty-one thousand, three hundred thirteen".
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