Base | Representation |
---|---|
bin | 10101000100101111… |
… | …11111010001100001 |
3 | 1002012111112110102100 |
4 | 22202113333101201 |
5 | 141132404211230 |
6 | 5110405041013 |
7 | 550242351525 |
oct | 124227772141 |
9 | 32174473370 |
10 | 11314132065 |
11 | 4886594975 |
12 | 22390b6169 |
13 | 10b4032a02 |
14 | 7948c1d85 |
15 | 463440660 |
hex | 2a25ff461 |
11314132065 has 96 divisors (see below), whose sum is σ = 21471840000. Its totient is φ = 5489358336.
The previous prime is 11314132057. The next prime is 11314132121. The reversal of 11314132065 is 56023141311.
It is a happy number.
11314132065 is a `hidden beast` number, since 11 + 31 + 413 + 206 + 5 = 666.
It is not a de Polignac number, because 11314132065 - 23 = 11314132057 is a prime.
It is a super-2 number, since 2×113141320652 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4933059 + ... + 4935351.
It is an arithmetic number, because the mean of its divisors is an integer number (223665000).
Almost surely, 211314132065 is an apocalyptic number.
11314132065 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11314132065 is a deficient number, since it is larger than the sum of its proper divisors (10157707935).
11314132065 is a wasteful number, since it uses less digits than its factorization.
11314132065 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2551 (or 2548 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 11314132065 its reverse (56023141311), we get a palindrome (67337273376).
The spelling of 11314132065 in words is "eleven billion, three hundred fourteen million, one hundred thirty-two thousand, sixty-five".
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