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11314204433 = 73743684187
BaseRepresentation
bin10101000100110000…
…10000111100010001
31002012111200010200122
422202120100330101
5141132414020213
65110410400025
7550243102520
oct124230207421
932174603618
1011314204433
114886634284
122239130015
1310b405992c
147949004b7
15463456d08
hex2a2610f11

11314204433 has 8 divisors (see below), whose sum is σ = 13279993152. Its totient is φ = 9435784176.

The previous prime is 11314204381. The next prime is 11314204537. The reversal of 11314204433 is 33440241311.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11314204433 - 216 = 11314138897 is a prime.

It is a super-2 number, since 2×113142044332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11314204933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21841835 + ... + 21842352.

It is an arithmetic number, because the mean of its divisors is an integer number (1659999144).

Almost surely, 211314204433 is an apocalyptic number.

It is an amenable number.

11314204433 is a deficient number, since it is larger than the sum of its proper divisors (1965788719).

11314204433 is an equidigital number, since it uses as much as digits as its factorization.

11314204433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43684231.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 11314204433 its reverse (33440241311), we get a palindrome (44754445744).

The spelling of 11314204433 in words is "eleven billion, three hundred fourteen million, two hundred four thousand, four hundred thirty-three".

Divisors: 1 7 37 259 43684187 305789309 1616314919 11314204433