113143032041310 has 24 divisors (see below), whose sum is σ = 294171883307640. Its totient is φ = 30171475210992.

The previous prime is 113143032041293. The next prime is 113143032041311. The reversal of 113143032041310 is 13140230341311.

113143032041310 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 4 + 303 + 2 + 0 + 41 + 310 = 666.

It is a super-2 number, since 2×113143032041310² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113143032041311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 628572400140 + ... + 628572400319.

It is an arithmetic number, because the mean of its divisors is an integer number (12257161804485).

Almost surely, 2^{113143032041310} is an apocalyptic number.

113143032041310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113143032041310 is an abundant number, since it is smaller than the sum of its proper divisors (181028851266330).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113143032041310 is a wasteful number, since it uses less digits than its factorization.

113143032041310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1257144800472 (or 1257144800469 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 113143032041310 its reverse (13140230341311), we get a palindrome (126283262382621).

The spelling of 113143032041310 in words is "one hundred thirteen trillion, one hundred forty-three billion, thirty-two million, forty-one thousand, three hundred ten".