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11314321100 = 22521723173173
BaseRepresentation
bin10101000100110001…
…01101011011001100
31002012111220001201122
422202120231123030
5141132431233400
65110413100112
7550244066615
oct124230553314
932174801648
1011314321100
1148867039a5
122239187638
1310b409aa74
14794930c0c
1546347b685
hex2a262d6cc

11314321100 has 216 divisors, whose sum is σ = 27449159808. Its totient is φ = 4042137600.

The previous prime is 11314321063. The next prime is 11314321103. The reversal of 11314321100 is 112341311.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is not an unprimeable number, because it can be changed into a prime (11314321103) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 65400614 + ... + 65400786.

Almost surely, 211314321100 is an apocalyptic number.

11314321100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11314321100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13724579904).

11314321100 is an abundant number, since it is smaller than the sum of its proper divisors (16134838708).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11314321100 is a wasteful number, since it uses less digits than its factorization.

11314321100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 325 (or 301 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11314321100 its reverse (112341311), we get a palindrome (11426662411).

The spelling of 11314321100 in words is "eleven billion, three hundred fourteen million, three hundred twenty-one thousand, one hundred".