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113145250303 = 17101199331141
BaseRepresentation
bin110100101011111111…
…0111000000111111111
3101211001021202020200001
41221113332320013333
53323210141002203
6123551143215131
711113562521261
oct1512776700777
9354037666601
10113145250303
1143a915a9228
1219b181474a7
13a892009467
145694bd9b31
152e232cd91d
hex1a57fb81ff

113145250303 has 16 divisors (see below), whose sum is σ = 121595342400. Its totient is φ = 104905152000.

The previous prime is 113145250277. The next prime is 113145250327. The reversal of 113145250303 is 303052541311.

It is a happy number.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113145250303 is a prime.

It is a super-2 number, since 2×1131452503032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113145250003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 176113 + ... + 507253.

It is an arithmetic number, because the mean of its divisors is an integer number (7599708900).

Almost surely, 2113145250303 is an apocalyptic number.

113145250303 is a deficient number, since it is larger than the sum of its proper divisors (8450092097).

113145250303 is a wasteful number, since it uses less digits than its factorization.

113145250303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 331458.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 113145250303 its reverse (303052541311), we get a palindrome (416197791614).

The spelling of 113145250303 in words is "one hundred thirteen billion, one hundred forty-five million, two hundred fifty thousand, three hundred three".

Divisors: 1 17 101 199 1717 3383 20099 331141 341683 5629397 33445241 65897059 568569097 1120250003 6655602959 113145250303