Base | Representation |
---|---|
bin | 10101000101001010… |
… | …11001011000101111 |
3 | 1002012202011000212020 |
4 | 22202211121120233 |
5 | 141134304200040 |
6 | 5111012241223 |
7 | 550314261042 |
oct | 124245313057 |
9 | 32182130766 |
10 | 11317646895 |
11 | 4888575695 |
12 | 223a310213 |
13 | 10b49937a9 |
14 | 795158c59 |
15 | 4638d6cd0 |
hex | 2a295962f |
11317646895 has 32 divisors (see below), whose sum is σ = 19487770560. Its totient is φ = 5587875840.
The previous prime is 11317646849. The next prime is 11317646903. The reversal of 11317646895 is 59864671311.
It is a happy number.
11317646895 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11317646895 - 29 = 11317646383 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 348240 + ... + 379349.
It is an arithmetic number, because the mean of its divisors is an integer number (608992830).
Almost surely, 211317646895 is an apocalyptic number.
11317646895 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11317646895 is a deficient number, since it is larger than the sum of its proper divisors (8170123665).
11317646895 is a wasteful number, since it uses less digits than its factorization.
11317646895 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 727675.
The product of its digits is 1088640, while the sum is 51.
The spelling of 11317646895 in words is "eleven billion, three hundred seventeen million, six hundred forty-six thousand, eight hundred ninety-five".
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