Base | Representation |
---|---|
bin | 10000011110001000001… |
… | …110000000000110011111 |
3 | 11000012112101121102022120 |
4 | 100132020032000012133 |
5 | 122021023103130110 |
6 | 2223545313514023 |
7 | 144526406211120 |
oct | 20361016000637 |
9 | 4005471542276 |
10 | 1131861770655 |
11 | 3a7024509960 |
12 | 163442272913 |
13 | 82970aaa2c5 |
14 | 3cad4ca8047 |
15 | 1e697c85870 |
hex | 1078838019f |
1131861770655 has 64 divisors (see below), whose sum is σ = 2261564817408. Its totient is φ = 469608888960.
The previous prime is 1131861770617. The next prime is 1131861770681. The reversal of 1131861770655 is 5560771681311.
It is not a de Polignac number, because 1131861770655 - 26 = 1131861770591 is a prime.
It is a super-2 number, since 2×11318617706552 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131861770598 and 1131861770607.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 106137 + ... + 1508306.
It is an arithmetic number, because the mean of its divisors is an integer number (35336950272).
Almost surely, 21131861770655 is an apocalyptic number.
1131861770655 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1131861770655 is a deficient number, since it is larger than the sum of its proper divisors (1129703046753).
1131861770655 is a wasteful number, since it uses less digits than its factorization.
1131861770655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1615076.
The product of its (nonzero) digits is 1058400, while the sum is 51.
The spelling of 1131861770655 in words is "one trillion, one hundred thirty-one billion, eight hundred sixty-one million, seven hundred seventy thousand, six hundred fifty-five".
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