Search a number
-
+
113200103303 = 716171443329
BaseRepresentation
bin110100101101101000…
…0000111111110000111
3101211012002222001211122
41221123100013332013
53323313211301203
6124000423024155
711115130000460
oct1513320077607
9354162861748
10113200103303
114400a564091
1219b3259b05b
13a8a04a3761
14569c1d7d67
152e28016538
hex1a5b407f87

113200103303 has 4 divisors (see below), whose sum is σ = 129371546640. Its totient is φ = 97028659968.

The previous prime is 113200103293. The next prime is 113200103381. The reversal of 113200103303 is 303301002311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113200103303 is a prime.

It is a super-3 number, since 3×1132001033033 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113200103503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8085721658 + ... + 8085721671.

It is an arithmetic number, because the mean of its divisors is an integer number (32342886660).

Almost surely, 2113200103303 is an apocalyptic number.

113200103303 is a deficient number, since it is larger than the sum of its proper divisors (16171443337).

113200103303 is an equidigital number, since it uses as much as digits as its factorization.

113200103303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16171443336.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 113200103303 its reverse (303301002311), we get a palindrome (416501105614).

The spelling of 113200103303 in words is "one hundred thirteen billion, two hundred million, one hundred three thousand, three hundred three".

Divisors: 1 7 16171443329 113200103303