Search a number
-
+
11320023 = 3111326387
BaseRepresentation
bin101011001011…
…101011010111
3210022010011010
4223023223113
510344220043
61042343303
7165134661
oct53135327
923263133
1011320023
1164319a0
12395ab33
132464650
141709531
15ed9133
hexacbad7

11320023 has 16 divisors (see below), whose sum is σ = 17732736. Its totient is φ = 6332640.

The previous prime is 11320019. The next prime is 11320031. The reversal of 11320023 is 32002311.

It is a happy number.

It is not a de Polignac number, because 11320023 - 22 = 11320019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11319990 and 11320008.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11320003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12765 + ... + 13622.

It is an arithmetic number, because the mean of its divisors is an integer number (1108296).

Almost surely, 211320023 is an apocalyptic number.

11320023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11320023 is a deficient number, since it is larger than the sum of its proper divisors (6412713).

11320023 is a wasteful number, since it uses less digits than its factorization.

11320023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26414.

The product of its (nonzero) digits is 36, while the sum is 12.

The square root of 11320023 is about 3364.5241862706. The cubic root of 11320023 is about 224.5341670840.

Adding to 11320023 its reverse (32002311), we get a palindrome (43322334).

It can be divided in two parts, 11 and 320023, that multiplied together give a palindrome (3520253).

The spelling of 11320023 in words is "eleven million, three hundred twenty thousand, twenty-three".

Divisors: 1 3 11 13 33 39 143 429 26387 79161 290257 343031 870771 1029093 3773341 11320023