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11320120221300 = 22335211631760337
BaseRepresentation
bin1010010010111010101110…
…1111101001111001110100
31111002012012122022211221000
42210232223233221321310
52440432101234040200
640024220314523300
72245565063155212
oct244565357517164
944065178284830
1011320120221300
113674921828280
121329ab9436530
13641637801147
142b1c7a935cb2
151496e0430300
hexa4babbe9e74

11320120221300 has 288 divisors, whose sum is σ = 39707404813440. Its totient is φ = 2743791667200.

The previous prime is 11320120221281. The next prime is 11320120221307. The reversal of 11320120221300 is 312202102311.

11320120221300 is a `hidden beast` number, since 1 + 1 + 3 + 20 + 120 + 221 + 300 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11320120221307) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 187584732 + ... + 187645068.

It is an arithmetic number, because the mean of its divisors is an integer number (137872933380).

Almost surely, 211320120221300 is an apocalyptic number.

11320120221300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11320120221300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19853702406720).

11320120221300 is an abundant number, since it is smaller than the sum of its proper divisors (28387284592140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11320120221300 is a wasteful number, since it uses less digits than its factorization.

11320120221300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66688 (or 66675 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11320120221300 its reverse (312202102311), we get a palindrome (11632322323611).

The spelling of 11320120221300 in words is "eleven trillion, three hundred twenty billion, one hundred twenty million, two hundred twenty-one thousand, three hundred".