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113201401 is a prime number
BaseRepresentation
bin1101011111101…
…01000011111001
321220000020010111
412233311003321
5212434421101
615122144321
72543124145
oct657650371
9256006114
10113201401
1158998985
1231ab20a1
131a5b65a1
141106a225
159e11251
hex6bf50f9

113201401 has 2 divisors, whose sum is σ = 113201402. Its totient is φ = 113201400.

The previous prime is 113201393. The next prime is 113201441. The reversal of 113201401 is 104102311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105781225 + 7420176 = 10285^2 + 2724^2 .

It is a cyclic number.

It is not a de Polignac number, because 113201401 - 23 = 113201393 is a prime.

It is not a weakly prime, because it can be changed into another prime (113201441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600700 + 56600701.

It is an arithmetic number, because the mean of its divisors is an integer number (56600701).

Almost surely, 2113201401 is an apocalyptic number.

It is an amenable number.

113201401 is a deficient number, since it is larger than the sum of its proper divisors (1).

113201401 is an equidigital number, since it uses as much as digits as its factorization.

113201401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 113201401 is about 10639.6147016704. The cubic root of 113201401 is about 483.7458666883.

Adding to 113201401 its reverse (104102311), we get a palindrome (217303712).

It can be divided in two parts, 11320 and 1401, that added together give a palindrome (12721).

The spelling of 113201401 in words is "one hundred thirteen million, two hundred one thousand, four hundred one".