Base | Representation |
---|---|
bin | 10101000101011101… |
… | …11101100000011100 |
3 | 1002012220212102011011 |
4 | 22202232331200130 |
5 | 141140424413030 |
6 | 5111142105004 |
7 | 550344502561 |
oct | 124256754034 |
9 | 32186772134 |
10 | 11320154140 |
11 | 4889a28399 |
12 | 223b11b164 |
13 | 10b5360a79 |
14 | 79560c868 |
15 | 463c2eb2a |
hex | 2a2bbd81c |
11320154140 has 48 divisors (see below), whose sum is σ = 25430261472. Its totient is φ = 4217757696.
The previous prime is 11320154137. The next prime is 11320154143. The reversal of 11320154140 is 4145102311.
11320154140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (11320154137) and next prime (11320154143).
It is a super-3 number, since 3×113201541403 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11320154143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 138642 + ... + 204601.
It is an arithmetic number, because the mean of its divisors is an integer number (529797114).
Almost surely, 211320154140 is an apocalyptic number.
11320154140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11320154140 is an abundant number, since it is smaller than the sum of its proper divisors (14110107332).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11320154140 is a wasteful number, since it uses less digits than its factorization.
11320154140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 343366 (or 343364 counting only the distinct ones).
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 11320154140 its reverse (4145102311), we get a palindrome (15465256451).
The spelling of 11320154140 in words is "eleven billion, three hundred twenty million, one hundred fifty-four thousand, one hundred forty".
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