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113204205451 is a prime number
BaseRepresentation
bin110100101101101111…
…1110001011110001011
3101211012101200110221001
41221123133301132023
53323320234033301
6124001050555431
711115206604211
oct1513337613613
9354171613831
10113204205451
1144011906097
1219b33a38b77
13a8a12ab96c
14569c984cb1
152e28576c01
hex1a5b7f178b

113204205451 has 2 divisors, whose sum is σ = 113204205452. Its totient is φ = 113204205450.

The previous prime is 113204205449. The next prime is 113204205479. The reversal of 113204205451 is 154502402311.

It is an a-pointer prime, because the next prime (113204205479) can be obtained adding 113204205451 to its sum of digits (28).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113204205451 - 21 = 113204205449 is a prime.

It is a super-2 number, since 2×1132042054512 (a number of 23 digits) contains 22 as substring.

Together with 113204205449, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (113204205481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56602102725 + 56602102726.

It is an arithmetic number, because the mean of its divisors is an integer number (56602102726).

Almost surely, 2113204205451 is an apocalyptic number.

113204205451 is a deficient number, since it is larger than the sum of its proper divisors (1).

113204205451 is an equidigital number, since it uses as much as digits as its factorization.

113204205451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 113204205451 its reverse (154502402311), we get a palindrome (267706607762).

The spelling of 113204205451 in words is "one hundred thirteen billion, two hundred four million, two hundred five thousand, four hundred fifty-one".