Base | Representation |
---|---|
bin | 110100101101110010… |
… | …0001110010111110111 |
3 | 101211012110212202200122 |
4 | 1221123210032113313 |
5 | 3323321033404112 |
6 | 124001132002155 |
7 | 11115222534341 |
oct | 1513344162767 |
9 | 354173782618 |
10 | 113205372407 |
11 | 44012532916 |
12 | 19b3430035b |
13 | a8a15c9b7a |
14 | 569cbaa291 |
15 | 2e28707872 |
hex | 1a5b90e5f7 |
113205372407 has 2 divisors, whose sum is σ = 113205372408. Its totient is φ = 113205372406.
The previous prime is 113205372391. The next prime is 113205372409. The reversal of 113205372407 is 704273502311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113205372407 - 24 = 113205372391 is a prime.
Together with 113205372409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113205372409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56602686203 + 56602686204.
It is an arithmetic number, because the mean of its divisors is an integer number (56602686204).
Almost surely, 2113205372407 is an apocalyptic number.
113205372407 is a deficient number, since it is larger than the sum of its proper divisors (1).
113205372407 is an equidigital number, since it uses as much as digits as its factorization.
113205372407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 35280, while the sum is 35.
Adding to 113205372407 its reverse (704273502311), we get a palindrome (817478874718).
The spelling of 113205372407 in words is "one hundred thirteen billion, two hundred five million, three hundred seventy-two thousand, four hundred seven".
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