Base | Representation |
---|---|
bin | 10101000101101101… |
… | …00001101111001111 |
3 | 1002020001121011212211 |
4 | 22202312201233033 |
5 | 141141431400201 |
6 | 5111252411251 |
7 | 550400403244 |
oct | 124266415717 |
9 | 32201534784 |
10 | 11322137551 |
11 | 489006257a |
12 | 223b916b27 |
13 | 10b58a679a |
14 | 7959a75cb |
15 | 463ec2651 |
hex | 2a2da1bcf |
11322137551 has 2 divisors, whose sum is σ = 11322137552. Its totient is φ = 11322137550.
The previous prime is 11322137549. The next prime is 11322137579. The reversal of 11322137551 is 15573122311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11322137551 - 21 = 11322137549 is a prime.
Together with 11322137549, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11322137501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661068775 + 5661068776.
It is an arithmetic number, because the mean of its divisors is an integer number (5661068776).
Almost surely, 211322137551 is an apocalyptic number.
11322137551 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322137551 is an equidigital number, since it uses as much as digits as its factorization.
11322137551 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6300, while the sum is 31.
Adding to 11322137551 its reverse (15573122311), we get a palindrome (26895259862).
The spelling of 11322137551 in words is "eleven billion, three hundred twenty-two million, one hundred thirty-seven thousand, five hundred fifty-one".
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