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113222111123000 = 23531197669115859
BaseRepresentation
bin11001101111100110010011…
…101101101101011000111000
3112211212221001121002011122002
4121233212103231231120320
5104320012340421414000
61040445304135320132
732564012314256255
oct3157462355553070
9484787047064562
10113222111123000
1133092256042040
1210847253b20048
134b23a50caba59
141dd5d9d74442c
15d152786598d5
hex66f993b6d638

113222111123000 has 256 divisors, whose sum is σ = 292066868620800. Its totient is φ = 40738567680000.

The previous prime is 113222111122969. The next prime is 113222111123003. The reversal of 113222111123000 is 321111222311.

It is a super-2 number, since 2×1132221111230002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113222111123003) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7139289071 + ... + 7139304929.

It is an arithmetic number, because the mean of its divisors is an integer number (1140886205550).

Almost surely, 2113222111123000 is an apocalyptic number.

113222111123000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113222111123000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (146033434310400).

113222111123000 is an abundant number, since it is smaller than the sum of its proper divisors (178844757497800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113222111123000 is a wasteful number, since it uses less digits than its factorization.

113222111123000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22679 (or 22665 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 113222111123000 its reverse (321111222311), we get a palindrome (113543222345311).

It can be divided in two parts, 1132221 and 11123000, that added together give a palindrome (12255221).

The spelling of 113222111123000 in words is "one hundred thirteen trillion, two hundred twenty-two billion, one hundred eleven million, one hundred twenty-three thousand".