Base | Representation |
---|---|
bin | 1010010011001101010100… |
… | …1011010111111110011111 |
3 | 1111002200002102002011220110 |
4 | 2210303111023113332133 |
5 | 2441022311220233210 |
6 | 40030403414021103 |
7 | 2246132535260046 |
oct | 244632513277637 |
9 | 44080072064813 |
10 | 11325110321055 |
11 | 3676a52593063 |
12 | 132aa70647793 |
13 | 641c515a46ab |
14 | 2b21d157b55d |
15 | 1498d357d420 |
hex | a4cd52d7f9f |
11325110321055 has 16 divisors (see below), whose sum is σ = 18505712185344. Its totient is φ = 5911546947360.
The previous prime is 11325110321051. The next prime is 11325110321081. The reversal of 11325110321055 is 55012301152311.
It is not a de Polignac number, because 11325110321055 - 22 = 11325110321051 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11325110321051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8031992431 + ... + 8031993840.
It is an arithmetic number, because the mean of its divisors is an integer number (1156607011584).
Almost surely, 211325110321055 is an apocalyptic number.
11325110321055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11325110321055 is a deficient number, since it is larger than the sum of its proper divisors (7180601864289).
11325110321055 is a wasteful number, since it uses less digits than its factorization.
11325110321055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16063986326.
The product of its (nonzero) digits is 4500, while the sum is 30.
Adding to 11325110321055 its reverse (55012301152311), we get a palindrome (66337411473366).
The spelling of 11325110321055 in words is "eleven trillion, three hundred twenty-five billion, one hundred ten million, three hundred twenty-one thousand, fifty-five".
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