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11325154101245 = 52265030820249
BaseRepresentation
bin1010010011001101011111…
…0010011000011111111101
31111002200012110110110000222
42210303113302120133331
52441022403422214440
640030412020231125
72246133606351065
oct244632762303775
944080173413028
1011325154101245
113676a75275836
12132aa8323b4a5
13641c5a692a2a
142b21d72d63a5
151498d732a2b5
hexa4cd7c987fd

11325154101245 has 4 divisors (see below), whose sum is σ = 13590184921500. Its totient is φ = 9060123280992.

The previous prime is 11325154101227. The next prime is 11325154101253. The reversal of 11325154101245 is 54210145152311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4594107831769 + 6731046269476 = 2143387^2 + 2594426^2 .

It is a cyclic number.

It is not a de Polignac number, because 11325154101245 - 28 = 11325154100989 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1132515410120 + ... + 1132515410129.

It is an arithmetic number, because the mean of its divisors is an integer number (3397546230375).

Almost surely, 211325154101245 is an apocalyptic number.

It is an amenable number.

11325154101245 is a deficient number, since it is larger than the sum of its proper divisors (2265030820255).

11325154101245 is an equidigital number, since it uses as much as digits as its factorization.

11325154101245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2265030820254.

The product of its (nonzero) digits is 24000, while the sum is 35.

Adding to 11325154101245 its reverse (54210145152311), we get a palindrome (65535299253556).

The spelling of 11325154101245 in words is "eleven trillion, three hundred twenty-five billion, one hundred fifty-four million, one hundred one thousand, two hundred forty-five".

Divisors: 1 5 2265030820249 11325154101245