Base | Representation |
---|---|
bin | 110100101111010100… |
… | …1010100100010010001 |
3 | 101211100002002202022211 |
4 | 1221132221110202101 |
5 | 3323422300240032 |
6 | 124010215232121 |
7 | 11116420645642 |
oct | 1513651244221 |
9 | 354302082284 |
10 | 113257040017 |
11 | 44039712520 |
12 | 19b49678641 |
13 | a8ac21a314 |
14 | 56a59b96c9 |
15 | 2e2d011747 |
hex | 1a5ea54891 |
113257040017 has 64 divisors (see below), whose sum is σ = 136515456000. Its totient is φ = 92806560000.
The previous prime is 113257040009. The next prime is 113257040077. The reversal of 113257040017 is 710040752311.
It is not a de Polignac number, because 113257040017 - 23 = 113257040009 is a prime.
It is a super-2 number, since 2×1132570400172 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (113257040077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 165822558 + ... + 165823240.
It is an arithmetic number, because the mean of its divisors is an integer number (2133054000).
Almost surely, 2113257040017 is an apocalyptic number.
It is an amenable number.
113257040017 is a deficient number, since it is larger than the sum of its proper divisors (23258415983).
113257040017 is a wasteful number, since it uses less digits than its factorization.
113257040017 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1102.
The product of its (nonzero) digits is 5880, while the sum is 31.
Adding to 113257040017 its reverse (710040752311), we get a palindrome (823297792328).
The spelling of 113257040017 in words is "one hundred thirteen billion, two hundred fifty-seven million, forty thousand, seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •