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113300220034 = 2431317444419
BaseRepresentation
bin110100110000100111…
…0000010100010000010
3101211110002100112011201
41221201032002202002
53324014324020114
6124014400531414
711120453660131
oct1514116024202
9354402315151
10113300220034
1144061025291
1219b60020b6a
13a8b8158421
1456ab619918
152e31be0874
hex1a61382882

113300220034 has 8 divisors (see below), whose sum is σ = 173902663440. Its totient is φ = 55332665556.

The previous prime is 113300220023. The next prime is 113300220043. The reversal of 113300220034 is 430022003311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1133002200342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113300219993 and 113300220020.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 658722124 + ... + 658722295.

It is an arithmetic number, because the mean of its divisors is an integer number (21737832930).

Almost surely, 2113300220034 is an apocalyptic number.

113300220034 is a deficient number, since it is larger than the sum of its proper divisors (60602443406).

113300220034 is a wasteful number, since it uses less digits than its factorization.

113300220034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1317444464.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 113300220034 its reverse (430022003311), we get a palindrome (543322223345).

The spelling of 113300220034 in words is "one hundred thirteen billion, three hundred million, two hundred twenty thousand, thirty-four".

Divisors: 1 2 43 86 1317444419 2634888838 56650110017 113300220034