| Base | Representation |
|---|---|
| bin | 110100110000100111… |
| … | …0000010100010000001 |
| 3 | 101211110002100112011200 |
| 4 | 1221201032002202001 |
| 5 | 3324014324020113 |
| 6 | 124014400531413 |
| 7 | 11120453660130 |
| oct | 1514116024201 |
| 9 | 354402315150 |
| 10 | 113300220033 |
| 11 | 44061025290 |
| 12 | 19b60020b69 |
| 13 | a8b8158420 |
| 14 | 56ab619917 |
| 15 | 2e31be0873 |
| hex | 1a61382881 |
113300220033 has 192 divisors, whose sum is σ = 227267948544. Its totient is φ = 52488000000.
The previous prime is 113300220023. The next prime is 113300220043. The reversal of 113300220033 is 330022003311.
113300220033 is a `hidden beast` number, since 113 + 300 + 220 + 0 + 33 = 666.
It is an interprime number because it is at equal distance from previous prime (113300220023) and next prime (113300220043).
It is not a de Polignac number, because 113300220033 - 25 = 113300220001 is a prime.
It is a zygodrome in base 10.
It is a junction number, because it is equal to n+sod(n) for n = 113300219988 and 113300220015.
It is not an unprimeable number, because it can be changed into a prime (113300220023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 50332158 + ... + 50334408.
It is an arithmetic number, because the mean of its divisors is an integer number (1183687232).
Almost surely, 2113300220033 is an apocalyptic number.
113300220033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113300220033 is the 194337-th octagonal number.
It is an amenable number.
113300220033 is an abundant number, since it is smaller than the sum of its proper divisors (113967728511).
113300220033 is a wasteful number, since it uses less digits than its factorization.
113300220033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2476 (or 2473 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 18.
Adding to 113300220033 its reverse (330022003311), we get a palindrome (443322223344).
It can be divided in two parts, 113300 and 220033, that added together give a palindrome (333333).
The spelling of 113300220033 in words is "one hundred thirteen billion, three hundred million, two hundred twenty thousand, thirty-three".
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