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1133004011999 = 9280912207911
BaseRepresentation
bin10000011111001100010…
…011010011100111011111
311000022110222221021212112
4100133030103103213133
5122030343011340444
62224254520024235
7144566616125606
oct20371423234737
94008428837775
101133004011999
113a7560255772
1216370090207b
1382ac362aa62
143cba2880a3d
151e7131b269e
hex107cc4d39df

1133004011999 has 4 divisors (see below), whose sum is σ = 1133016312720. Its totient is φ = 1132991711280.

The previous prime is 1133004011989. The next prime is 1133004012011. The reversal of 1133004011999 is 9991104003311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1133004011999 - 28 = 1133004011743 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133004011959) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6011147 + ... + 6196764.

It is an arithmetic number, because the mean of its divisors is an integer number (283254078180).

Almost surely, 21133004011999 is an apocalyptic number.

1133004011999 is a deficient number, since it is larger than the sum of its proper divisors (12300721).

1133004011999 is an equidigital number, since it uses as much as digits as its factorization.

1133004011999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12300720.

The product of its (nonzero) digits is 26244, while the sum is 41.

The spelling of 1133004011999 in words is "one trillion, one hundred thirty-three billion, four million, eleven thousand, nine hundred ninety-nine".

Divisors: 1 92809 12207911 1133004011999