Base | Representation |
---|---|
bin | 10000011111001100010… |
… | …011010011100111011111 |
3 | 11000022110222221021212112 |
4 | 100133030103103213133 |
5 | 122030343011340444 |
6 | 2224254520024235 |
7 | 144566616125606 |
oct | 20371423234737 |
9 | 4008428837775 |
10 | 1133004011999 |
11 | 3a7560255772 |
12 | 16370090207b |
13 | 82ac362aa62 |
14 | 3cba2880a3d |
15 | 1e7131b269e |
hex | 107cc4d39df |
1133004011999 has 4 divisors (see below), whose sum is σ = 1133016312720. Its totient is φ = 1132991711280.
The previous prime is 1133004011989. The next prime is 1133004012011. The reversal of 1133004011999 is 9991104003311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1133004011999 - 28 = 1133004011743 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1133004011959) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6011147 + ... + 6196764.
It is an arithmetic number, because the mean of its divisors is an integer number (283254078180).
Almost surely, 21133004011999 is an apocalyptic number.
1133004011999 is a deficient number, since it is larger than the sum of its proper divisors (12300721).
1133004011999 is an equidigital number, since it uses as much as digits as its factorization.
1133004011999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12300720.
The product of its (nonzero) digits is 26244, while the sum is 41.
The spelling of 1133004011999 in words is "one trillion, one hundred thirty-three billion, four million, eleven thousand, nine hundred ninety-nine".
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