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1133004012000 = 253537231394219
BaseRepresentation
bin10000011111001100010…
…011010011100111100000
311000022110222221021212120
4100133030103103213200
5122030343011341000
62224254520024240
7144566616125610
oct20371423234740
94008428837776
101133004012000
113a7560255773
12163700902080
1382ac362aa63
143cba2880a40
151e7131b26a0
hex107cc4d39e0

1133004012000 has 768 divisors, whose sum is σ = 4459301683200. Its totient is φ = 245872281600.

The previous prime is 1133004011989. The next prime is 1133004012011. The reversal of 1133004012000 is 2104003311.

It is an interprime number because it is at equal distance from previous prime (1133004011989) and next prime (1133004012011).

It is a super-2 number, since 2×11330040120002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 268545891 + ... + 268550109.

It is an arithmetic number, because the mean of its divisors is an integer number (5806382400).

Almost surely, 21133004012000 is an apocalyptic number.

1133004012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1133004012000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2229650841600).

1133004012000 is an abundant number, since it is smaller than the sum of its proper divisors (3326297671200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1133004012000 is a wasteful number, since it uses less digits than its factorization.

1133004012000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4416 (or 4398 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1133004012000 its reverse (2104003311), we get a palindrome (1135108015311).

The spelling of 1133004012000 in words is "one trillion, one hundred thirty-three billion, four million, twelve thousand".