Base | Representation |
---|---|
bin | 10101000110101001… |
… | …01101110001010011 |
3 | 1002020121111020022021 |
4 | 22203110231301103 |
5 | 141200443114110 |
6 | 5112134152311 |
7 | 550524563053 |
oct | 124324556123 |
9 | 32217436267 |
10 | 11330051155 |
11 | 4894578145 |
12 | 22424b2697 |
13 | 10b74177a7 |
14 | 796a67563 |
15 | 464a372da |
hex | 2a352dc53 |
11330051155 has 4 divisors (see below), whose sum is σ = 13596061392. Its totient is φ = 9064040920.
The previous prime is 11330051143. The next prime is 11330051171. The reversal of 11330051155 is 55115003311.
It is a happy number.
11330051155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11330051155 - 29 = 11330050643 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1133005111 + ... + 1133005120.
It is an arithmetic number, because the mean of its divisors is an integer number (3399015348).
Almost surely, 211330051155 is an apocalyptic number.
11330051155 is a deficient number, since it is larger than the sum of its proper divisors (2266010237).
11330051155 is an equidigital number, since it uses as much as digits as its factorization.
11330051155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2266010236.
The product of its (nonzero) digits is 1125, while the sum is 25.
Adding to 11330051155 its reverse (55115003311), we get a palindrome (66445054466).
The spelling of 11330051155 in words is "eleven billion, three hundred thirty million, fifty-one thousand, one hundred fifty-five".
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