Base | Representation |
---|---|
bin | 110100110000111001… |
… | …1101110111100110111 |
3 | 101211110202221112201122 |
4 | 1221201303232330313 |
5 | 3324024341220203 |
6 | 124015352414155 |
7 | 11120633653400 |
oct | 1514163567467 |
9 | 354422845648 |
10 | 113310101303 |
11 | 44066664223 |
12 | 19b633a735b |
13 | a8ba207c29 |
14 | 56aca6c9a7 |
15 | 2e329e3538 |
hex | 1a61ceef37 |
113310101303 has 6 divisors (see below), whose sum is σ = 131809709736. Its totient is φ = 97122943932.
The previous prime is 113310101297. The next prime is 113310101351. The reversal of 113310101303 is 303101013311.
It is not a de Polignac number, because 113310101303 - 210 = 113310100279 is a prime.
It is a super-2 number, since 2×1133101013032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113310101603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1156225475 + ... + 1156225572.
It is an arithmetic number, because the mean of its divisors is an integer number (21968284956).
Almost surely, 2113310101303 is an apocalyptic number.
113310101303 is a deficient number, since it is larger than the sum of its proper divisors (18499608433).
113310101303 is an equidigital number, since it uses as much as digits as its factorization.
113310101303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2312451061 (or 2312451054 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 113310101303 its reverse (303101013311), we get a palindrome (416411114614).
The spelling of 113310101303 in words is "one hundred thirteen billion, three hundred ten million, one hundred one thousand, three hundred three".
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