| Base | Representation |
|---|---|
| bin | 1010010011100011011000… |
| … | …1101000010001100111000 |
| 3 | 1111010020101011212012120220 |
| 4 | 2210320312031002030320 |
| 5 | 2441121423434112100 |
| 6 | 40033223232020040 |
| 7 | 2246432364212160 |
| oct | 244706615021470 |
| 9 | 44106334765526 |
| 10 | 11331033113400 |
| 11 | 367951187a670 |
| 12 | 1330044091620 |
| 13 | 64268667a050 |
| 14 | 2b25d400d5a0 |
| 15 | 149b2d514aa0 |
| hex | a4e36342338 |
11331033113400 has 1152 divisors, whose sum is σ = 48475082396160. Its totient is φ = 2114491392000.
The previous prime is 11331033113357. The next prime is 11331033113401. The reversal of 11331033113400 is 431133013311.
It is a super-2 number, since 2×113310331134002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331033113401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 822214510 + ... + 822228290.
It is an arithmetic number, because the mean of its divisors is an integer number (42079064580).
Almost surely, 211331033113400 is an apocalyptic number.
11331033113400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11331033113400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24237541198080).
11331033113400 is an abundant number, since it is smaller than the sum of its proper divisors (37144049282760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11331033113400 is a wasteful number, since it uses less digits than its factorization.
11331033113400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13905 (or 13859 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 11331033113400 its reverse (431133013311), we get a palindrome (11762166126711).
The spelling of 11331033113400 in words is "eleven trillion, three hundred thirty-one billion, thirty-three million, one hundred thirteen thousand, four hundred".
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