Base | Representation |
---|---|
bin | 1010010011100011101011… |
… | …0011100001000001111101 |
3 | 1111010020120120010012102201 |
4 | 2210320322303201001331 |
5 | 2441122103214410023 |
6 | 40033235030351501 |
7 | 2246434322321164 |
oct | 244707263410175 |
9 | 44106516105381 |
10 | 11331110310013 |
11 | 367955140661a |
12 | 1330065abb591 |
13 | 642699668410 |
14 | 2b26003863db |
15 | 149b351b2bad |
hex | a4e3ace107d |
11331110310013 has 8 divisors (see below), whose sum is σ = 12920542073208. Its totient is φ = 9844222531584.
The previous prime is 11331110309951. The next prime is 11331110310019. The reversal of 11331110310013 is 31001301113311.
11331110310013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 1439563233124 + 9891547076889 = 1199818^2 + 3145083^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11331110310013 - 29 = 11331110309501 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331110310019) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25635995956 + ... + 25635996397.
It is an arithmetic number, because the mean of its divisors is an integer number (1615067759151).
Almost surely, 211331110310013 is an apocalyptic number.
11331110310013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11331110310013 is a deficient number, since it is larger than the sum of its proper divisors (1589431763195).
11331110310013 is a wasteful number, since it uses less digits than its factorization.
11331110310013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51271992383.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 11331110310013 its reverse (31001301113311), we get a palindrome (42332411423324).
The spelling of 11331110310013 in words is "eleven trillion, three hundred thirty-one billion, one hundred ten million, three hundred ten thousand, thirteen".
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