11331131121013 has 4 divisors (see below), whose sum is σ = 12361233950208. Its totient is φ = 10301028291820.

The previous prime is 11331131121007. The next prime is 11331131121029. The reversal of 11331131121013 is 31012113113311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331131121013 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331131121083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 515051414581 + ... + 515051414602.

It is an arithmetic number, because the mean of its divisors is an integer number (3090308487552).

Almost surely, 2^{11331131121013} is an apocalyptic number.

It is an amenable number.

11331131121013 is a deficient number, since it is larger than the sum of its proper divisors (1030102829195).

11331131121013 is a wasteful number, since it uses less digits than its factorization.

11331131121013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1030102829194.

The product of its (nonzero) digits is 162, while the sum is 22.

Adding to 11331131121013 its reverse (31012113113311), we get a palindrome (42343244234324).

The spelling of 11331131121013 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, one hundred twenty-one thousand, thirteen".