11331131203031 has 2 divisors, whose sum is σ = 11331131203032. Its totient is φ = 11331131203030.

The previous prime is 11331131203009. The next prime is 11331131203033. The reversal of 11331131203031 is 13030213113311.

It is a strong prime.

It is an emirp because it is prime and its reverse (13030213113311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331131203031 is a prime.

It is a super-2 number, since 2×11331131203031² (a number of 27 digits) contains 22 as substring.

Together with 11331131203033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11331131202988 and 11331131203006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331131203033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565601515 + 5665565601516.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565601516).

Almost surely, 2^{11331131203031} is an apocalyptic number.

11331131203031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131203031 is an equidigital number, since it uses as much as digits as its factorization.

11331131203031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 11331131203031 its reverse (13030213113311), we get a palindrome (24361344316342).

The spelling of 11331131203031 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred three thousand, thirty-one".