Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011010010010001101111 |
3 | 1111010020122000110121001112 |
4 | 2210320330003102101233 |
5 | 2441122124043033403 |
6 | 40033241054502235 |
7 | 2246434665133361 |
oct | 244707403222157 |
9 | 44106560417045 |
10 | 11331131221103 |
11 | 3679562199411 |
12 | 1330070b0497b |
13 | 6426a0aaa445 |
14 | 2b260306ad31 |
15 | 149b36e439d8 |
hex | a4e3c0d246f |
11331131221103 has 4 divisors (see below), whose sum is σ = 11500252582680. Its totient is φ = 11162009859528.
The previous prime is 11331131221099. The next prime is 11331131221139. The reversal of 11331131221103 is 30112213113311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11331131221103 - 22 = 11331131221099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331131221703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84560680688 + ... + 84560680821.
It is an arithmetic number, because the mean of its divisors is an integer number (2875063145670).
Almost surely, 211331131221103 is an apocalyptic number.
11331131221103 is a deficient number, since it is larger than the sum of its proper divisors (169121361577).
11331131221103 is an equidigital number, since it uses as much as digits as its factorization.
11331131221103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 169121361576.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 11331131221103 its reverse (30112213113311), we get a palindrome (41443344334414).
The spelling of 11331131221103 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred twenty-one thousand, one hundred three".
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