Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011101101010110010111 |
3 | 1111010020122000200020011111 |
4 | 2210320330003231112113 |
5 | 2441122124110110431 |
6 | 40033241101115451 |
7 | 2246434666104562 |
oct | 244707403552627 |
9 | 44106560606144 |
10 | 11331131331991 |
11 | 3679562264759 |
12 | 1330070b58b87 |
13 | 6426a0b18a63 |
14 | 2b26030994d9 |
15 | 149b36e667b1 |
hex | a4e3c0ed597 |
11331131331991 has 2 divisors, whose sum is σ = 11331131331992. Its totient is φ = 11331131331990.
The previous prime is 11331131331901. The next prime is 11331131332093. The reversal of 11331131331991 is 19913313113311.
It is a weak prime.
It is an emirp because it is prime and its reverse (19913313113311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11331131331991 - 217 = 11331131200919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331131331901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565665995 + 5665565665996.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565665996).
Almost surely, 211331131331991 is an apocalyptic number.
11331131331991 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131331991 is an equidigital number, since it uses as much as digits as its factorization.
11331131331991 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 19683, while the sum is 40.
The spelling of 11331131331991 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred thirty-one thousand, nine hundred ninety-one".
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