Base | Representation |
---|---|
bin | 10000011111010010110… |
… | …011100110111100111101 |
3 | 11000022202121021201121012 |
4 | 100133102303212330331 |
5 | 122031103431034401 |
6 | 2224313415045005 |
7 | 144602412541232 |
oct | 20372263467475 |
9 | 4008677251535 |
10 | 1133113143101 |
11 | 3a7606913565 |
12 | 163731370765 |
13 | 82b1011a784 |
14 | 3cbb316b789 |
15 | 1e71ca6c8bb |
hex | 107d2ce6f3d |
1133113143101 has 2 divisors, whose sum is σ = 1133113143102. Its totient is φ = 1133113143100.
The previous prime is 1133113143023. The next prime is 1133113143143. The reversal of 1133113143101 is 1013413113311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 939183883225 + 193929259876 = 969115^2 + 440374^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133113143101 - 230 = 1132039401277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133113143181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566556571550 + 566556571551.
It is an arithmetic number, because the mean of its divisors is an integer number (566556571551).
Almost surely, 21133113143101 is an apocalyptic number.
It is an amenable number.
1133113143101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133113143101 is an equidigital number, since it uses as much as digits as its factorization.
1133113143101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 1133113143101 its reverse (1013413113311), we get a palindrome (2146526256412).
The spelling of 1133113143101 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred forty-three thousand, one hundred one".
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