11331132000101 has 4 divisors (see below), whose sum is σ = 11331167277600. Its totient is φ = 11331096722604.

The previous prime is 11331132000091. The next prime is 11331132000103. The reversal of 11331132000101 is 10100023113311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11331132000101 - 2¹⁸ = 11331131737957 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11331132000101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331132000103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17152481 + ... + 17800838.

It is an arithmetic number, because the mean of its divisors is an integer number (2832791819400).

Almost surely, 2^{11331132000101} is an apocalyptic number.

It is an amenable number.

11331132000101 is a deficient number, since it is larger than the sum of its proper divisors (35277499).

11331132000101 is an equidigital number, since it uses as much as digits as its factorization.

11331132000101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35277498.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11331132000101 its reverse (10100023113311), we get a palindrome (21431155113412).

The spelling of 11331132000101 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, one hundred one", and thus it is an aban number.