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113312023123303 is a prime number
BaseRepresentation
bin11001110000111010000010…
…111000110001010101100111
3112212012112010201101000212101
4121300322002320301111213
5104323001010404421203
61040554454053432531
732603344364541034
oct3160720270612547
9485175121330771
10113312023123303
11331173a5018704
121086076733b747
134b2c37c7cc6b4
141dda48ca9638b
15d1778be0241d
hex670e82e31567

113312023123303 has 2 divisors, whose sum is σ = 113312023123304. Its totient is φ = 113312023123302.

The previous prime is 113312023123289. The next prime is 113312023123309. The reversal of 113312023123303 is 303321320213311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113312023123303 - 233 = 113303433188711 is a prime.

It is a super-2 number, since 2×1133120231233032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113312023123309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656011561651 + 56656011561652.

It is an arithmetic number, because the mean of its divisors is an integer number (56656011561652).

Almost surely, 2113312023123303 is an apocalyptic number.

113312023123303 is a deficient number, since it is larger than the sum of its proper divisors (1).

113312023123303 is an equidigital number, since it uses as much as digits as its factorization.

113312023123303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 28.

Adding to 113312023123303 its reverse (303321320213311), we get a palindrome (416633343336614).

The spelling of 113312023123303 in words is "one hundred thirteen trillion, three hundred twelve billion, twenty-three million, one hundred twenty-three thousand, three hundred three".