Base | Representation |
---|---|
bin | 10000011111010011111… |
… | …011101000010101110011 |
3 | 11000022210220210221011110 |
4 | 100133103323220111303 |
5 | 122031123244220110 |
6 | 2224315331444403 |
7 | 144603032164146 |
oct | 20372373502563 |
9 | 4008726727143 |
10 | 1133132023155 |
11 | 3a7616539410 |
12 | 163737756703 |
13 | 82b13ccb1c2 |
14 | 3cbb588405d |
15 | 1e71e54ba20 |
hex | 107d3ee8573 |
1133132023155 has 32 divisors (see below), whose sum is σ = 2031285328128. Its totient is φ = 534548764800.
The previous prime is 1133132023139. The next prime is 1133132023157. The reversal of 1133132023155 is 5513202313311.
It is not a de Polignac number, because 1133132023155 - 24 = 1133132023139 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1133132023157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 92797501 + ... + 92809710.
It is an arithmetic number, because the mean of its divisors is an integer number (63477666504).
Almost surely, 21133132023155 is an apocalyptic number.
1133132023155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1133132023155 is a deficient number, since it is larger than the sum of its proper divisors (898153304973).
1133132023155 is a wasteful number, since it uses less digits than its factorization.
1133132023155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 185607267.
The product of its (nonzero) digits is 8100, while the sum is 30.
Adding to 1133132023155 its reverse (5513202313311), we get a palindrome (6646334336466).
The spelling of 1133132023155 in words is "one trillion, one hundred thirty-three billion, one hundred thirty-two million, twenty-three thousand, one hundred fifty-five".
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